In the circuit below there are two identical bulbs. The switch has been open for

Question

In the circuit below there are two identical bulbs. The switch has been open for a long time and the capacitor is uncharged. The battery is ideal and has a voltage (Vbat) of 12.0 volts.

QUESTION 1: Just after the switch is closed, rank the magnitudes of the four voltages Vbat, VA, VB, and Vcap. Choose the correct option

A: VA = VB > Vcap > Vbat

B: Vbat > VA = VB > Vcap

C:Vbat = VA = VB > Vcap

D: Vbat = VA = VB = Vcap

E: Vbat = VA = Vcap > VB

QUESTION 2: After the switch has been closed for a long time, rank the magnitudes of the currents ibat, iA, and iB. Choose the correct option.

A: iA > iB = ibat

B: ibat = iA = iB

C: ibat > iA = iB

D: ibat = iA > iB

QUESTION 3: Now the Switch is Opened.

Just after the switch is opened, what is the magnitude of the voltage across bulb A?

Explanation / Answer

answer is C

C:Vbat = VA = VB > Vcap

answer is D

D: ibat = iA > iB

voltage across capacitor is V=12 =eqaul to batery voltage

now switch is open this capacitor act as voltages source to the two identical bulbs i.e each having same resistance.

so the voltage drop across bulb A=12/2 =6 v

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