1. The average power plant, running at full capacity, puts out 500. MW of power.

Question

1. The average power plant, running at full capacity, puts out 500. MW of power. If the power company charges its customers $0.10 per kWh, what is the revenue brought in by the power plant each day?

2. Sherm is typing his term paper on a computer that contains a high-speed switch, controlled with a small

100x 10^-12 F speed-up capacitor. What is the current flow created by the capacitor if it discharges every 0.1 s across a potential difference of 5 V?

3. An 800.-W submersible electric heater is put into a 20.0

Explanation / Answer

Given

Power P=500 MW

Need it in KW

P=500*103KW

Total Energy Consumed in 1 day i.e 24 Hours

E=P*t =500*103*24

E=1.2*107KWH

Cost

C=1.2*107*0.1

C=$ 1.2*106

2.

Current across a Capacitor

I=C*(dV/dt)

I=(100*10-12)*(5/0.1)

I=5*10-9A or 5 nA

3.

Q=mC*dT =50*4187*(70-20)

Q=10,467,500 J

time taken by the heater to heat the tub is

t=Q/P =10,467,500/800

t==13084.4 seconds or 3.6345 Hours

4.

a)

Since 2 bulbs are connected in series ,equivalent resistance

R=2+2=4 ohms

Current drawn by horrace reading glasses

I=V/R =3.2/4

I=0.8 A

b)

Energy Consumed in 5 Hours

E=V*I*t=0.8*3.2*5*60*60

E=46080 J

here 46080 J greater than 5184 J

so Energy depletion occurs

b)

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