5.15. In the gure is shown the cycle for a Carnot refrigerator. This cycle is th
ID: 1308673 • Letter: 5
Question
5.15. In the gure is shown the cycle for a Carnot refrigerator. This cycle is the same as the
Carnot engine except that the direction along each path is reversed. Paths A and C are
adiabatic (Q = 0), and paths B and D are isothermal (T = 0). Consider the working
substance of this refrigerator to be an ideal gas. Fill in the chart below as in the previous
problem. Now, using your completed chart, answer the following question. Is the work
done on the gas along path B positive, negative, or zero?
5.16. In the previous problem, is the change in internal energy of the gas along path C
positive, negative, or zero?
5.17. In the previous problem, is the heat put into the gas along path D positive, negative, or
zero?
5.18. In the previous problem, is the change in internal energy the gas along path D positive,
negative, or zero?
5.19. In the previous problem, is the net work done on the gas during the entire cycle positive,
negative, or zero?
5.20. In the previous problem, is the net change in internal energy of the gas during the entire
cycle positive, negative, or zero?
Explanation / Answer
5.16
Q = 0 while gas contracts this means work is done on the system combining these two conditions & apply first law of thermodynamics change in internal energy is positive
5.17
sinct T = constant it means change in internal enertgy = 0 again work is done on the system
so heat input is positive
5.18
change in internal energy = 0
change in internal energy is function of change in temperature
5.19
NET WORK DONE ON THE GAS POSITIVE by obseving the cycle
5.20
net change = change along A+ B + C +D
Change along A = negative along B = zero along C = positive along D = zero
obviously magnitude of change along A is less than change along D so net chnge is positive
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