You are cooking breakfast for yourself and a friend using a 1100 W waffle iron a

Question

You are cooking breakfast for yourself and a friend using a 1100 W waffle iron and a 460 W coffeepot. Usually, you operate these appliances from a 110 V outlet for 0.500 h each day. (a) At 12 cents per kWh, how much do you spend to cook breakfast during a 30.0 day period? $=__________

(b) You find yourself addicted to waffles and would like to upgrade to a 2200 W waffle iron that will enable you to cook twice as many waffles during a half-hour period, but you know that the circuit breaker in your kitchen is a 20 A breaker. Can you do the upgrade?

Give the current that this new waffle iron (along with the coffee pot) draws to support your answer.
I =________ A

Explanation / Answer

Total Power Consumed

P=1100+460

P=1560 Watts=1.56 KW

Total Energy Consumed in a day if it is used for 0.5 hour for 30 days

P=E*t =1.560*(0.5*30)

P=23.4 KWH

Cost

C=12*23.4 =280.8 cents or $2.808

b)

Now total power

P=2200+460

P=2660 W

Current

I=V/P =2660/110 =24.18 A

No you cannot upgrade since Consumed Current rating is more than the Circuit braker rating .

I=24.18 A

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