Question for my lab report. Here are my data and here is the graph and here are

Question

Question for my lab report.

Here are my data

and here is the graph

and here are the Questions. (Please read all A and B)

Position the microphone as close to the speaker as you can, which we will call a distance of d-0cm from the speaker. Adjust the oscilloscope and signal generator controls to give a pattern on the screen that is as large as possible and shirt the largest spike to the left of the screen. Align the CURSOR for T1 to the spike of the pattern. This pattern will look different from the patterns we have seen so far. As you move the microphone away from the speaker, the time delay for the signal to travel the greater distance will be seen as the pattern spike shirts to the right across the oscilloscope screen. Align the CURSOR for T2 to the spike as it shirt across the screen. The value of the time delay is Delta t. Measure the time delay for distances from 0 to 100cm, in 10cm increments. Include uncertainty values for the distances and the delay times. Make a graph showing the speaker-to-microphone distance as a function of the delay time, with error bars. Fit a straight line to the graph. Physics 222 students, compute the least-squares best-tit line to your data (see Ch. 8 in Taylor). Find the speed of sound in the laboratory from the slope of your graph. Compare your result to 34000cm/s, which is the standard value for the speed of sound in air at standard temperature and pressure. What is the speed of sound from your graph? What is the percent discrepancy? Why does your value for speed of sound differ from the known value of speed of sound? Using the VOLTAGE menu, find and record the signal strength at 20cm. 40cm. and 60cm with the signal generator amplitude setting fixed. How do you expect the V values to be related?

Explanation / Answer

Question 1)

The slope of your graph is y/x

That is 2.85 X 10-3 sec/100 cm

That is 2.85 X 10-5 s/cm

The inverse is 1/2.85 X 10-5 = 35087 cm/s For your speed of sound

The percent discrepency is [(35087-34000)/34000] X 100

That is 3.20%

Question 2)

The known value for the speed of sound is based on a temperature of 20o Celsius. If it was warmer in the location of the experiment, the speed of sound will be larger. Additionally, humidity plays a large role and possible air currents in the room. For example if the air conditioning system is on, the flow of the air will alter the speed of sound calculation, and again can show an increase in the value.

I am guessing thats all you need for now since we don;t have any information provided for question 3.

Hope this helps, please ask if you have any questons. I used to teach Physics and can help further if needed. Thanks!

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