Three identical blocks are initially at rest on a level, frictionless surface. A
ID: 1310076 • Letter: T
Question
Three identical blocks are initially at rest on a level, frictionless surface. At t = 0 s, the same force is exerted at a different point on each block, as shown in the top-view diagram below. The point of application of each force is indicated by an "X"; the location of the center of mass of each block, by a dot. For each of the blocks, draw an arrow on the diagram above to indicate the direction of the acceleration of the block's center of mass at the instant shown. If the magnitude of the acceleration of the center of mass of any block is zero, state so explicitly. Explain.Explanation / Answer
Block 1, the angular acceleration will be clockwise. Block 2, the angular acceleration will be zero. Block 3, the angular acceleration will be counter-clockwise.
The angular acceleration of block 3 is the greatest.
Next is block 1, and the last is block 2 for which the angular acceleration is zero.
Block 1 will have a negative direction, block 2 will equal zero, and block 3 will have a positive direction.
The centers of mass of all blocks will accelerate away in the direction of the force in a straight line with differing amounts of block spinning. This happens because there is still a horizontal component of the force that will move the whole block
Block 2 will never have an angular acceleration because the force is directly into the axis. Block 3 will have the greatest angular velocity because it has the most force causing rotational motion. Block 1 is in between
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.