An air a frictionless horizontal to a string and allowed to revolve in a circle

Question

An air a frictionless horizontal to a string and allowed to revolve in a circle of radius 1.1 m on a frictionless horizontal table. The other end of the string passes m tied through a hole in the center of the table, and a mass of 1.5 kg is tied to it. The suspended mass remains in equilibrium while the puck on the tabletop revolves. (a) What is the tension in the string? 10.78 Your response differs from the correct answer by more than 10%. Double check your calculations. N (b) What is the force causing the centripetal acceleration on the puck? 10.78 Your response differs from the correct answer by more than 10%. Double check your calculations. N (c) What is the speed of the puck? 7.74 m/s

Explanation / Answer

a)
Tension in the rope is equal to the centripetal force , which is equal to the weight of the block .

T = mg
T = 1.5(9.8)
T = 14.7 N

b)
centripetal force = mV

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