please show steps to solve number 9 and 10. The answers are E) 3V and C) 48W. Nu
ID: 1311368 • Letter: P
Question
please show steps to solve number 9 and 10. The answers are E) 3V and C) 48W. Number 8 is D if you need it
For questions 8 through 10, you are considering the circuit diagram to the right, which is composed of three resistors and two batteries. There are also three points (a, b, and c) in the circuit you that you will be examining (these are just points in the wire and have no circuit elements at those locations). When referring to current in these questions, please note that we are always referring to conventional current. What is the direction of current at points a, b, and c? The current moves to the right at point a, to the left at point b, and upward at point c. The current moves to the right at point a, to the left at point b, and upward at point c. The current moves to the left at point a, to the left at point b, and upward at point c . The current moves to the left at point a, to the left at point b, and downward at point c. The current moves to the left at point a, to the right at point b, and downward at point c. What is the voltage drop across the 3 Ohm resistor? What is the power dissipated by the 12 Ohm resistor?Explanation / Answer
Le current I1 flow through point A in anti-clockwise direction. I2 flow through B in anti-clockwise direction and So, (I2 - I1) goes downward in C
Thus, applying loop law:
42 - 12 (I1) + 3 ( I2 - I1) - 21 = 0
Thus,
21 = 15I1 - 3I2
Applying loop law to the outer loop.
42 - 12 I1 - 6 I2 = 0
Thus,
12 I1 + 6 I2 = 42
Solving both the equations simultaneously, we have:
I1 = 2 A
I2 = 3A
NOw, answering the questions:
Current through 3 ohm = (I2 - I1) = 3-2 = 1 A
Thus, voltage drop across it = I * R = 1 * 3 = 3V
And,
Power across 12ohm = I2R = 2 * 2 * 12 = 48 W
Hope this helps. Please rate it ASAP. Thanks.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.