A javelin thrower standing at rest holds the center of the javelin behind her he

Question

A javelin thrower standing at rest holds the center of the javelin behind her head, then accelerates it through a distance of 65 cm as she throws. She releases the javelin 2.2 m above the ground traveling at an angle 30 degrees above the horizontal. TOp rated javelin throwers do throw at about a 30 degrees angle, not the 45 degrees you might have expected, because the biomechanics of the arm allow them to throw the javelin much faster at 30 degrees than they would be able to at 45 degrees. In this throw, the javelin hits the gorund 60.1 m away. What was the acceleration of the javelin during the throw? Assume that it has a constant acceleration.

Explanation / Answer

First, you need to find the velocity at which the javelin leaves her hand.

Say that velocity is V.

Horizontal component of V:
Vh = V

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