http://puu.sh/9LRvY/c71d63f132.png Two straight parallel wires carry currents in
ID: 1314327 • Letter: H
Question
http://puu.sh/9LRvY/c71d63f132.png
Two straight parallel wires carry currents in opposite directions as shown in the figure. One of the wires carries a current of I2 = 10.6 A. Point A is the midpoint between the wires. The total distance between the wires is d = 10.9 cm. Point C is 5.72 cm to the right of the wire carrying current I2. Current I1 is adjusted so that the magnetic field at C is zero. Calculate the value of the current I1.
Calculate the magnitude of the magnetic field at point A.
What is the force between two 1.25 m long segments of the wires?
Explanation / Answer
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Two straight parallel wires carry currents in opposite directions as shown in the figure. One of the wires carries a current of I2 = 10.4 A. Point A is the midpoint between the wires. The total distance between the wires is d = 11.7 cm. Point C is 5.26 cm to the right of the wire carrying current I2. Current I1 is adjusted so that the magnetic field at C is zero. Calculate the value of the current I1.
Calculate the magnitude of the magnetic field at point A.
What is the force between two 2.27 m long segments of the wires?
Answer
For the magnetic field to be zero, I2/d2 = I1/d1, so I1 = (10.4/5.26)*(11.7+5.26) = 33.5 A.
The magnetic field at point A is ?0I1/(2?*.0585) + ?0I2/(2?*.0585) = 4? x 10-7*(33.5+10.4)/(2?*.0585)= 4.75 x 10^-5 T.
The force between 2.27 m segments is d*B*A = 2.27*10.4*33.5*4? x 10-7/(2?*.0117) = .135 N, repulsive.
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