14) The electric potential immediately outside a charged conducting sphere is 22

Question

14) The electric potential immediately outside a charged conducting sphere is 220 V, and 10.0 cm farther from the center of the sphere the potential is 140 V.

(a) Determine the radius of the sphere.
cm

(b) Determine the charge on the sphere.
nC

The electric potential immediately outside another charged conducting sphere is 250 V, and 10.0 cm farther from the center the magnitude of the electric field is 360 V/m. (c) Determine all possible values for the radius of the sphere. (Enter your answers from smallest to largest. If only one value exists, enter "NONE" in the second answer blank.)

(d) Determine the charge on the sphere for each value of r. (If only one value exists, enter "NONE" in the second answer blank.)

Explanation / Answer

apply Electric potential V = KQ/r

when r = 0.1m V = 140 V

s0 using this data

Charge Q = Vr/k

Q = 140 * 0.1/9e9

Q = 1.56 nC

so now when V = 220 V

r =    KQ/V

so

r = 9e9 *1.56e-9/(220)

r = 6.4 cm
------------------------------

Charge Q = Vr/k

Q = 140 * 0.1/9e9

Q = 1.56 nC
-----------------------------------

C. use for electric field E = KQ/r^2

so Charge Q = Er^2./K

Q = 360 * 0.1*0.1/9e9

Q = 4 e-10 C

----------------------

now agian use

V = KQ/r

so

r = 9e9 * 4e-10/250

r 1.44 cm

-----------------

d.
so Charge Q = Er^2./K

Q = 360 * 0.1*0.1/9e9

Q = 4 e-10 C

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