Three point charges are on the x axis: q1 is at the origin, q2 is at x 3.6 m, an

Question

Three point charges are on the x axis: q1 is at the origin, q2 is at x 3.6 m, and q3 is at x 6.9 m Find the electrostatic potential energy of this system of charges for the following charge values. (Assume the potential energy is zero when the charges are very far from each other.) 1) (a) q q2 q3 2.2 JC mJ mit You currently have 8 submissions for this question. Only 10 submission are allowed. You can make 2 more submissions for this question. (b) q q2 2.9 HC and q3 2.9 HC 6.30 mJ mit You currently have 1 submissions for this question. Only 10 submission are allowed. You can make 9 more submissions for this question. Your submissions 6.30 x Computed value: 6.30 Submitted Tuesday, February 17 at 4:08 PM Feedback: (c) q q3 2.9 HC and q2 2.9 HC mJ mit You currently have o submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question.

Explanation / Answer

1) U = k*[(q1*q2/r1)+(q2*q3/r2)+(q3*q1/r3)]

     U = 9*10^9*[((2.2*2.2*10^-12)/3.6)+((2.2*2.2*10^-12)/(6.9-3.6))+(2.2*2.2*10^-12/(6.9))]
U = 3.52 mJ

2) U = k*[(q1*q2/r1)+(q2*q3/r2)+(q3*q1/r3)]

U = 9*e9*[((2.9*2.9*e-12)/3.6)-((2.9*2.9*e-12)/(6.9-3.6))-(2.9*2.9*e-12/(6.9))]

U = -1.44 mJ
3) U = k*[(q1*q2/r1)+(q2*q3/r2)+(q3*q1/r3)]

U = 9*e9*[-((2.9*2.9*e-12)/3.6)-((2.9*2.9*e-12)/(6.9-3.6))+(2.9*2.9*e-12/(6.9))]

U = -3.67 mJ

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.