I need help with Part B, please. A 10 k g crate is placed on a horizontal convey

Question

I need help with Part B, please.

A 10kg crate is placed on a horizontal conveyor belt. The materials are such that ?s=0.5 and ?k=0.3.

Part A

Draw a free-body diagram showing all the forces on the crate if the conveyer belt runs at constant speed.

Draw the force vectors with their tails at the dot. The orientation of your vectors will be graded. The exact length of your vectors will not be graded but the relative length of one to the other will be graded.

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Part B

Draw a free-body diagram showing all the forces on the crate if the conveyer belt is speeding up.

Draw the force vectors with their tails at the dot. The orientation of your vectors will be graded. The exact length of your vectors will not be graded but the relative length of one to the other will be graded.

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Part C

What is the maximum acceleration the belt can have without the crate slipping?

Express your answer to two significant figures and include the appropriate units.

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A 10kg crate is placed on a horizontal conveyor belt. The materials are such that ?s=0.5 and ?k=0.3.

Part A

Draw a free-body diagram showing all the forces on the crate if the conveyer belt runs at constant speed.

Draw the force vectors with their tails at the dot. The orientation of your vectors will be graded. The exact length of your vectors will not be graded but the relative length of one to the other will be graded.

SubmitMy AnswersGive Up

Correct

Part B

Draw a free-body diagram showing all the forces on the crate if the conveyer belt is speeding up.

Draw the force vectors with their tails at the dot. The orientation of your vectors will be graded. The exact length of your vectors will not be graded but the relative length of one to the other will be graded.

SubmitMy AnswersGive Up

Incorrect; Try Again; 2 attempts remaining

Part C

What is the maximum acceleration the belt can have without the crate slipping?

Express your answer to two significant figures and include the appropriate units.

SubmitMy AnswersGive Up

Correct

Explanation / Answer

The normal force and the weight are equal
Weight 10 * 9.8 = 98 N
Since the crate is staying in one place on the conveyer belt, use the static coefficient of friction.
Ff = 0.5 * 98 = 49 N

If the crate is not sliding as the conveyor belt accelerates, the horizontal force which the conveyor be exerting the bottom of the crate must be equal to the static friction force.

The length of the friction force vector is one half of the length of the other two vectors. The direction of the friction force vector is opposite the direction that the conveyor belt is moving

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