You are standing on a scale inside an elevator. The scale reads 133 percent of y

Question

You are standing on a scale inside an elevator. The scale reads 133 percent of your weight. What is the acceleration of the elevator?
(Define positive y upward.)

(Practice how to properly work this out. Start with a scetch of the situation. Then draw a proper force diagram, aka free-body diagram. Apply Newton's Law and find the answer. Practice how to explain all your steps along the way; what you are doing and why; explain why you are drawing the diagram the way you do. Finally, evaluate your answer.)

Explanation / Answer

since reading is more than weight,it means lift is moving downwards, accelearion is downwards

towards the -ve y axis

net force=weight reading=1.33mg

F=m(g+a)

1.33mg=mg+ma

0.33mg=ma

a=0.33*9.8=3.234 m/s2

its direction is downwards

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