I\'m currently working on this exercise. In (b) the solution was: (T1-T2)*x; but

Question

I'm currently working on this exercise. In (b) the solution was: (T1-T2)*x; but why ins't it: 1.5*2200 (mass of two objects)*x

icis aid the fore in newtons. 19. An elevator consists of an elevator cage and a counterweight attached to the ends of a cable that runs over a pulley (Fig. 7.27). The mass of the cage (with its load) is 1200 kg, and the mass of the counterweight is 1000 kg. The elevator is driven 0 m at a h. What is by an electric motor attached to the pulley. Suppose that the elevator is initially at rest on the first floor of the building and the motor makes the elevator accelerate upward at the ng an angle kg, and the e ramp 1s box to a man pushes e ramp. with its gears d of 110 rate of 1.5 m/s (a) What is the tension in the part of the cable attached to the ele- vator cage? What is the tension in the part of the cable attached to the counterweight? diagram for normal force rted by the de of the fric- tions? What is tomobile trav- (b) The acceleration lasts exactly 1.0 s. How much work has the 1200 kg electric motor done in this interval? Ignore friction forces and ignore the mass of the pulley hill, a driver f the automobile hill is 25, how the skid? IHow (e) After the acceleration interval of 1.0s, the motor pulls the elevator upward at constant speed until it reaches the third floor, exactly 10.0 m above the first floor. What is the total 1000 s traveling on a s the total work FIGURE 7.27 Elevator cage and amount of work that the motor s/st Ai 30m/s has done up to this point?

Explanation / Answer

The force applied by motor on Cage and counter weight is upward and is T1 and T2 respectively. The cage is moving in the direction of force whereas coumter weight is moving in opposite direction. Since, the string is same displacement of both would be same and is equal to x.

So, Work done= T1x-T2x=x(T1-T2)

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