Exercise 24.36 A parallel-plate capacitor has a capacitance of C 0 = 3.70pF when

ID: 1317312 • Letter: E

Question

Exercise 24.36

A parallel-plate capacitor has a capacitance of C0 = 3.70pF when there is air between the plates. The separation between the plates is 1.30mm .

Part A

What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates is not to exceed 3.00

Exercise 24.36

A parallel-plate capacitor has a capacitance of C0 = 3.70pF when there is air between the plates. The separation between the plates is 1.30mm .

Part A

What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates is not to exceed 3.00

PART 1 :

C = Q/V and E = V/d for parallel plates, where d is distance between then plates.

C = Q / (E d)

so, Q = C E d

Q = (3.70E-12)(3.0E4)(1.30E-3) = 1.44*10^-10 C

Q = 0.144 nC or 144 pC.

PART2:

The capacitance is multiplied by 2.8 here.

same eqn as in part 1

Q = C E d = (2.8)(3.7E-12)(3E4)(1.3E-3) = 4.04*10^-10 C

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