Two cars P and Q travel in the same direction on a long straight section of the

ID: 1317392 • Letter: T

Question

Two cars P and Q travel in the same direction on a long straight section of the highway. Car key passes car Q and is adjacent to car Q at time t0.
Suppose that car P and car Q each moves with a constant speed. At time T0 is the magnitude of the instantaneous velocity of car key greater than, less then, or equal to the magnitude of the instantaneous velocity of car Q? Explain.
Now suppose instead that car P is moving with constant speed but car Q is speeding up. At time T0 is the magnitude of the instantaneous velocity of car P greater than, less then, or equal to the magnitude of the instantaneous velocity of car Q? Explain.

I've been at this question for hours. I believe it has to do with the formula for instantaneous velocity. v= lim t->0 x2-x1/t2-t1. But I am unsure of my answers any help would be nice. Two cars P and Q travel in the same direction on a long straight section of the highway. Car key passes car Q and is adjacent to car Q at time t0.
Suppose that car P and car Q each moves with a constant speed. At time T0 is the magnitude of the instantaneous velocity of car key greater than, less then, or equal to the magnitude of the instantaneous velocity of car Q? Explain.
Now suppose instead that car P is moving with constant speed but car Q is speeding up. At time T0 is the magnitude of the instantaneous velocity of car P greater than, less then, or equal to the magnitude of the instantaneous velocity of car Q? Explain.

I've been at this question for hours. I believe it has to do with the formula for instantaneous velocity. v= lim t->0 x2-x1/t2-t1. But I am unsure of my answers any help would be nice.
Suppose that car P and car Q each moves with a constant speed. At time T0 is the magnitude of the instantaneous velocity of car key greater than, less then, or equal to the magnitude of the instantaneous velocity of car Q? Explain.
Now suppose instead that car P is moving with constant speed but car Q is speeding up. At time T0 is the magnitude of the instantaneous velocity of car P greater than, less then, or equal to the magnitude of the instantaneous velocity of car Q? Explain.

I've been at this question for hours. I believe it has to do with the formula for instantaneous velocity. v= lim t->0 x2-x1/t2-t1. But I am unsure of my answers any help would be nice.

Explanation / Answer

First part Solution :- Lets assume Speed of car P = Vp

Speed of car Q = Vq

Both car P and Q are moving at constant speed. But car P is passing or Overtaking car Q . that means

speed of car P > speed of car Q

Vp > Vq

When speed os constant , instanteneuse speed is same as constant speed

Hence instanteneous velocity of P > instanteneuse velocity of Q

Second part Solution :-

Car P is moving at constant speed P

Car Q is moving at some Positive acceleration ( speeding up)

But at time To , car P is overtaking Q, that means instanteneous speed of P is greater than instanteneous speed of car Q

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