A 5.0-kg mass with an initial velocity of 4.0 m/s, east collides with a 4.0-kg m

Question

A 5.0-kg mass with an initial velocity of 4.0 m/s, east collides with a 4.0-kg mass with an initial velocity of 3.0 m/s, west. After the collision the 5.0-kg mass has a velocity of 1.2 m/s, west. What is the magnitude of the velocity of the 4.0-kg mass after the collision?

ANS: 3.5 m/s 4. A 6.0-kg object moving 2.0 m/s in the positive x direction has a one-dimensional elastic collision with a
4.0-kg object moving 3.0 m/s in the opposite direction. What is the total kinetic energy of the two-mass system after the collision?

ANS: 30 J

PLEASE SHOW WORK

Explanation / Answer

for elastic collision, v1'=(m1-m2)*v1/(m1+m2) + 2m2*v2/(m1+m2) and v2'= 2m1*v1/(m1+m2) + (m2-m1)*v2/(m1+m2)

so v1'=2.8 m/s and v2'=1.8 m/s so total kinetic energy= (m1(v1')^2)/2 + (m2(v2')^2)/2= 30j

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