NOTE THIS PROBLEM ONLY HAS ONE QUESTION In one model of a person jogging, the en
ID: 1318790 • Letter: N
Question
NOTE THIS PROBLEM ONLY HAS ONE QUESTION
In one model of a person jogging, the energy expended is assumed to go into accelerating and decelerating the feet and the lower portions of the legs. If the jogging speed is v, then the maximum speed of the foot and lower leg is about 2v. (From the moment a foot leaves the ground, to the moment it next contacts the ground, the foot travels nearly twice as far as the torso, so it must be going, on average, nearly twice as fast as the torso.) If the mass of the foot and lower portion of a leg is m, the energy needed to accelerate the foot and lower portion of a leg from rest to speed 2v is 1/2 m(2v)2= 2mv2, and the same energy is needed to decelerate this mass back to rest for the next stride. Assume that the mass of the foot and lower portion of a man's leg is 5.6 kg and that he jogs at a speed of 2.8 m/s with 1.0 m between one footfall and the next. The energy he must provide to each leg in each 2.0 m of travel is 2mv2, so the energy he must provide to both legs during each second of jogging is 6mv2. Calculate the rate of the man's energy expenditure using this model, assuming that his muscles have an efficiency of 23 percent.
Explanation / Answer
The rate of the man
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