Identical 53 mu C charges are fixed on an x axis at x = plus minus 3.3 m. A part

Question

Identical 53 mu C charges are fixed on an x axis at x = plus minus 3.3 m. A particle of charge q = -15 mu C is then released from rest at a point on the positive part of the y axis. Due to the symmetry of the situation, the particle moves along the y axis and has kinetic energy 1.4 J as it passes through the point x = 0, y = 3.6 m. (a) What is the kinetic energy of the particle as it passes through the origin? (b) At what negative value of y will the particle momentarily stop? (a) Number Units (b) Number Units

Explanation / Answer

mass m = 4.1-kg

velocity at origin v = +1.8 m/s

(a). the kinetic energy of the particle as it passes throughthe origin K = ( 1/ 2) m v ^ 2

                                                                                                       = 6.642 J

(b). work done W = area under curve and positonaxis

                            = ( 1/ 2) * 4 m* 6 N

                            = 12 J

(c). Kinetic energy at x = 4 is K ' = K + W

                                                     =18.642 J

we know K ' = ( 1/ 2) m v ' ^ 2

So, speed at x = 4 is v ' = ?[ 2K ' / m]

                                     = 3.015 m / s

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