In the latest Indian Jones film, Indy is supposed to throw a grenade from his ca

Question

In the latest Indian Jones film, Indy is supposed to throw a grenade from his car, which is going 80.0km/h , to his enemy's car, which is going 111km/h . The enemy's car is 16.3m in front of the Indy's when he lets go of the grenade.

Part A)If Indy throws the grenade so its initial velocity relative to him is at an angle of 45 ? above the horizontal, what should the magnitude of the initial velocity be? The cars are both traveling in the same direction on a level road. You can ignore air resistance.

Part B)Find the magnitude of the velocity relative to the earth.

Explanation / Answer

Part A)

The enemy's car is 16.3m in front of the Indy's when he lets go of the grenade.

(Vcos45 + Vj - Vc)* t = 16.3

t= 2Vsin45/g
(Vcos45 + 80- 111)* 2Vsin45/10 = 16.3

(Vcos45 -31)*V=115.25

V2-43.84V-163=0

SOLVING THIS EQUATION

V=47.28m/s

Part B)

velocity of earth is not given

grenade moves 47.28m/s withrespect to earth

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