A 38-turn circular coil of wire has a diameter of 1.7m. It is placed with its ax

Question

A 38-turn circular coil of wire has a diameter of 1.7m. It is placed with its axis along the direction of the Earth?s magnetic field of 38 MuT at 61 degrees below the horizontal, and then in 0.24s it is flipped 180 degree. a) What is volts the magnitude of the average induced emf in the coil? b) We would like 100 x the voltage found in part a to be generated between the wingtips of an airplane of 61.9 m wingspan flying horizontally in the same region. What would be in m/s the needed speed of the airplane?

Explanation / Answer

emf = (d/dt)*(flux)

e = (d/dt)*(N*B*A*costheta)

e = N*B*A*(cos(theta1) - cos(theta2))/dt

e = (38*38e-6*3.14*0.85*0.85*(cos61 - cos180)/0.24

emf = 0.0203 v

b) emf = B*v*L

100*0.013 = 38e-6*61.9*v

v = 863.02 m/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.