Q1:How does the current through the LED change when you switched between the two

Question

Q1:How does the current through the LED change when you switched between the two resistors? What does this tell you about how quickly charge is moving in the LED for each case?

Q2:Explain why the LED changes brightness when the resistors are switched according to Ohms Law.

Q3: Use Ohms Law to calculate the current (in Amps) traveling through a 100? resistor in series with a 3 V battery. Compare this to the current travelling through a 1 k? resistor.

Procedure 1. Set up the Snap Circuits as shown in Figure 5 using one LED and the 100 ohm resistor. 2. Flip the switch to the 'on' position, and note the brightness of the LED. 3. Replace the 100 ohm resistor with the 1 k Ohm resistor from the Snap Circuits materials. Switch back and forth a few times to notice any differences in the brightness of the LED.

Explanation / Answer

Q1:
More current flows when the 100 ohm resistor is placed in the circuit.LED glows brighter when more current flows through it
The brightness in the LED is LESS when the 1k(1000) Ohm resistor is placed and brighter for the 100 Ohm resistor
this tells us that charge is moving faster when the 100 ohm resistor is placed.

Q2:
According to ohm's law more current flows when there is lesser resistance offered.Hence more current will flow
when 100 ohm resistor is placed.
Led glows brighter when more current flows through it.So it is brighter when the 100 ohm resistor is placed in the circuit

Q3:
When 100 ohms is placed in series with a 3V battery, the current according to ohm's law is
I=V/R
I=3/100=0.03 Amperes
When a 1k ohm resistor is placed in series with a 3V battery, the current is,
I=V/R
I=3/1000=0.003 Amperes
Which is 10 times lesser compared to when the 100 Ohms was placed

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