The two wires shown in the figure below are separated by d = 10.5 cm and carry c

Question

The two wires shown in the figure below are separated by

d = 10.5 cm and carry currents of I = 5.15 A in opposite directions.

(a) Find the magnitude and direction of the net magnetic field at a point midway between the wires.

(a) Find the magnitude and direction of the net magnetic field at a point midway between the wires.

(c) Find the magnitude and direction of the net magnetic field at point P2, 2d = 21.0 cm to the left of the wire on the left.

The two wires shown in the figure below are separated by d = 10.5 cm and carry currents of I = 5.15 A in opposite directions. (a) Find the magnitude and direction of the net magnetic field at a point midway between the wires. (a) Find the magnitude and direction of the net magnetic field at a point midway between the wires. (c) Find the magnitude and direction of the net magnetic field at point P2, 2d = 21.0 cm to the left of the wire on the left.

Explanation / Answer

in my case both fields will be into the page and will have the same magnitude

So B = 2*(?o*I/2?r) = (but ?o/2? = 2.0X10^-7)

so B = 2*(2.0x10^-7*5.15/(0.105/2) = 3.923x10^-5T (IN)


c) Now the net field will be OUT

B = ?o/2?*(I1/0.21 - I2/(0.105 + 0.21)) = 2.0x10^-7*(5.15/0.21 - 5.15/(0.105 + 0.21) =

= 1.634x10^-6 T OUT

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