In the figure (Figure 1) , each capacitance C 1 is 8.7910 ?6 F , and each capaci

ID: 1321384 • Letter: I

Question

In the figure (Figure 1) , each capacitance C1 is 8.7910?6F , and each capacitance C2 is 5.8610?6F .

Part A

Compute the equivalent capacitance of the network between points a and b.

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Part B

Compute the charge on the three capacitors nearest a and b when Vab = 310V .

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Part C

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Part D

With 310V across a and b, compute Vcd.

Ceq = F In the figure (Figure 1) , each capacitance C1 is 8.79 10?6F , and each capacitance C2 is 5.86 10?6F . Part A Compute the equivalent capacitance of the network between points a and b. Ceq = F SubmitMy AnswersGive Up Part B Compute the charge on the three capacitors nearest a and b when Vab = 310V . Q1 = C SubmitMy AnswersGive Up Part C Q2 = C SubmitMy AnswersGive Up Part D With 310V across a and b, compute Vcd. Vcd = V SubmitMy AnswersGive Up

Explanation / Answer

Then, two 8.79 and one 5.86 are in series.

1/ C = 2 / 8.79 + 1/ [5.86]

=0.22+0.17

=2.5

second circuit is same as first one

=2.5

Then, three 8.79 are in series

1/ C = 3/ 8.79

=2.93uF

All three in parllel so add up

ceq=2.5+2.5+2.93

=7.93uF

b)Q = CV

=2.5*310

=775uC

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In the figure (Figure 1) , each capacitance C 1 is 8.7910 ?6 F , and each capaci

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