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(I keep getting the answer incorrect please help) The 2.3-cm-diameter solenoid i

ID: 1321696 • Letter: #

Question

(I keep getting the answer incorrect please help)
The 2.3-cm-diameter solenoid in (Figure 1) passes through the center of a

6.0-cm-diameter loop. The magnetic field inside the solenoid is 0.40T .

1.) What is the magnetic flux through the loop when it is perpendicular to the solenoid? Express two sig figs

Flux= _______________Wb

2.) What is the magnetic flux through the loop when it is tilted at a 60? angle? express two sig figs

flux=____________Wb

The 2.3-cm-diameter solenoid in (Figure 1) passes through the center of a 6.0-cm-diameter loop. The magnetic field inside the solenoid is 0.40T . 1.) What is the magnetic flux through the loop when it is perpendicular to the solenoid? Express two sig figs Flux= _______________Wb 2.) What is the magnetic flux through the loop when it is tilted at a 60? angle? express two sig figs flux=____________Wb

Explanation / Answer

The diameter of the solenoid d = 2.3cm

then the radius of the solenoid r = 1.15cm

the magnetic filed B = 0.40T

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PART-A

The magnetic flux through the loop:

flux=(magnetic field)(area)(costheta)

phi = BAcos(theta)

phi = 0.40*pi*(1.15*10^-2)^2 *1

flux = 1.661*10^-4 wb

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PART-B

when it is tilted at theta = 60

flux=(magnetic field)(area)(costheta)

fux = 0.40*pi*(1.15*10^-2)^2 *cos60

flux= 8.309*10^-5 wb

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