1) The following sequence of DNA is transcribed and encodes a small protein with
ID: 132186 • Letter: 1
Question
1) The following sequence of DNA is transcribed and encodes a small protein with the sequence Met Tyr Arg Gly Ala. 5*-CCTATGCCCGCATCATTACGCACCTCTGTACATGGC-3 3'-GGATACGGGCGTAGTAATGCGTGGAGACATGTACCC-5 a) Which strand of DNA is the template strand for transcription? Which direction (right to left or left to right) does RNA polymerase move it transcribes this gene? b) What Indicate the 5 and3' directions of this gene c) A single base mutation in the gene results in synthesis of the peptide Met Tyr. What is the sequence of nucleotides making up the mRNA produced by this mutant gene? along the template as is the sequence of the nucleotides in the processed mRNA molecule for this gene? 2) List three characteristics of the genetic code. 3) How can you distinguish experimentally among DNA polymerase III, RNA polymerase, and primase? you isolate a mutant bacterium that does not have an active ligase enzyme. Can this 4) Suppose bacterium replicate? Why or why not? At what step will replication be halted?Explanation / Answer
seq given is
5’- CCTATGCCCCGCATCATTACGCACCTCTGTACATGGC-3’
3’- GGATACGGGCGTAGTAATGCGTGGAGACATGTACCG-5’
mRNA 3’- GGA UAC GGG CGU AGU AAU GCG UGG AGA CAU GUA CCC- 5’
5’- GCC AUG UAC AGA GGU GCG UAA UGA UGC GGG CAU AGG –3’
The underlined and bold codon are the codon for given amino acids.
5’- GCTATGCCCCGCATCATTACGCACCTCTGTACATGGC-3’
It is forward strand so the RNA polymerase will move in 5’ to 3’ direction.
they are triplets of bases(A,U,G,C, in various combination).
The codes are non overlapping and comma is not placed in between two codes.
AUG is the start codon, Ochar, amber and opal are stop codons.
They are non ambiguous.
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