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Electromagnetic Induction A coil of N = 2500 turns on a cylinder of 80.0 cm radi

ID: 1322280 • Letter: E

Question

Electromagnetic Induction

A coil of N = 2500 turns on a cylinder of 80.0 cm radius, 1.20 m length, is placed in the
changing magnetic eld directly under 60.0 Hz power lines (two suspended north-south wires
with opposite currents) that generate an AC magnetic eld B(t) of amplitude B0 = 10:0 T
inside the coil.

a) From one negative peak to the next positive peak in B(t), what is the average rate
B=t, at which the magnetic eld is changing?

b) Estimate the maximum emf that the coil can produce. Show your symbolic calculation,
then calculate the number with units.

c) In what direction should the axis of the coil point to get the greatest emf? Draw a sketch
to support your answer.

Electromagnetic Induction A coil of N = 2500 turns on a cylinder of 80.0 cm radius, 1.20 m length, is placed in the changing magnetic eld directly under 60.0 Hz power lines (two suspended north-south wires with opposite currents) that generate an AC magnetic eld B(t) of amplitude B0 = 10:0 T inside the coil. a) From one negative peak to the next positive peak in B(t), what is the average rate B=t, at which the magnetic eld is changing? b) Estimate the maximum emf that the coil can produce. Show your symbolic calculation, then calculate the number with units. c) In what direction should the axis of the coil point to get the greatest emf? Draw a sketch to support your answer.

Explanation / Answer

a) here, time periode, T = 1/f = 1/60 = 1.67*10^-2 s

dB/dt = (B2-B1)/(t2-t1)

= (10-(-10))*10^-6/(T/2)

= 20*10^-6/(1.67*10^-2/2)

= 0.024 T/s <<<<<<<<<<<<<<<<------------------Answer

b) induced emf_max = N*A*B*w

= N*A*B*(2*pi*f)

= 2500*pi*0.8^2*10*10^-6*(2*pi*60)

= 18.95 volts <<<<<<<<<<<<<<<<------------------Answer


C) plane of the coil should be in vertical plain and axis should be parallel to east-west direction. <<<<<<<<<<<<<<<<------------------Answer

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