(a) when the field is perpendicular to the plane of the loop T m 2 (b) when the

Question

(a) when the field is perpendicular to the plane of the loop
T m2

(b) when the field makes a 60.0 angle with the normal to the plane of the loop
T m2

(c) when the field makes a 90.0 angle with the normal to the plane
T m2

Find the flux of Earth's magnetic field of magnitude 5.00 x 10^-5 T through a square loop of area 10.0 cm2 for the following: (a) when the field is perpendicular to the plane of the loop T I 1/2 m2 (b) when the field makes a 60.0 I 1/2 angle with the normal to the plane of the loop T I 1/2 m2 (c) when the field makes a 90.0 I 1/2 angle with the normal to the plane T I 1/2 m2

Explanation / Answer

flux = B A cos?

(a)   5.00 x 10-5 * 10.0 x10-4 * cos0 =

                 =   5.00 x10-8 T m2

(b)    5.00 x 10-5 * 10.0 x10-4 * cos60 =

                 = 2.5 x10-8 T m2

(c)    5.00 x 10-5 * 10.0 x10-4 * cos90 =

                 =   0 Tm2

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