Q7. Queen Victoria of England ruled the United Kingdom from 1837 until 1901. She

Question

Q7. Queen Victoria of England ruled the United Kingdom from 1837 until 1901. She and her husband had 9 children who married into other royal families around the world. She introduced the mutant gene for hemophilia into the royal family. Hemophilia is an inherited genetic disorder that impairs the body's ability to make blood clots, a process needed to stop bleeding. Historically, hemophilia has been described as “The Royal Disease” because of its prevalence in the British Royal family.

It is well established that hemophilia is an X-linked recessive disorder.

IMPORTANT: PLEASE READ

Use of notation when inputting answers on Blackboard.

Use X and Y to indicate the chromosomes and A or a to define the trait.

Proper notation would normally require the use of superscripts (for example A or a would be a superscript to X chromosome for X-linked traits (e.g. XAXa)), however, due to limitations in this online assessment tool, you are not required to use these superscripts. Please type A or a next to the X.  

Use the following notation in this assignment:

XAXA, XAXa, XaXa, XAY, XaY

(4 marks)

(a) A man with hemophilia would have the genotype:  

(b) A woman that is a carrier for hemophilia would have the genotype:

(c) If this man with hemophilia and woman (who is a carrier), were to have children:

(i) what percentage of their children would have hemophilia?  %

(ii) what percentage of their daughters would be a carrier for hemophilia?  %

HINT: you may find it helpful to generate a Punnett Square.

QUESTION 8

(2 marks)

The following pedigree follows a trait found in the Jones family.

What type of inheritance is most likely for this trait?

X-linked dominant

autosomal recessive

X-linked recessive

autosomal dominant

2 points   

QUESTION 9

(1 mark)

What is the genotype of individual I-1 based on the pedigree shown in Question 8 for the Jones family?

XAXA

XAXa

XaXa

AA

Aa

aa

QUESTION 10

What is the genotype of individual I-2 based on the pedigree shown in Question 8 for the Jones family?

XAY

XaY

AA

Aa

aa

1 points   

QUESTION 11

What is the genotype of individual II-5 based on the pedigree shown in Question 8 for the Jones family?

XAXA

XAXa

XaXa

AA

Aa

aa

1 points   

QUESTION 12

(1 mark)

What is the genotype of individual IV-4 based on the pedigree shown in Question 8 for the Jones family?

XAY

XaY

AA

Aa

aa

X-linked dominant

autosomal recessive

X-linked recessive

autosomal dominant

Explanation / Answer

Q7)a)A man with haemophilia will have genotype XaY.As haemophilia is X linked reccessive disorder .Since males have only one copy of X chromosome,only one allele is sufficient to cause the disease.

b)woman who is carrier of the disease will have genotype XAXa.Woman will have only one reccessive allele,so she will be a carrier.If two reccessive alleles are present ,she will have the disease.

c)If man who has haemophilia XaY and woman who is a carrier were to have children,their children will have folllowing genotype,XAXa,XaXa,XAY,XaY.

1. 50% of their children will have haemophilia.Those with genotype XaXa and XaY.

   2. 50% daughters will be carrier for haemophila.those with genotype (XAXa)

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