Three blocks are sliding along a frictionless track. Block A (mass 4.98 kg) is m

Question

Three blocks are sliding along a frictionless track. Block A (mass 4.98 kg) is moving to the right at 2.40 m/s. Block B (mass 2.49 kg) is moving to the right at 1.44 m/s. Block C (mass 3.80 kg) is at rest. What is the combined momentum of all 3 blocks?

Three blocks are sliding along a frictionless track. Block A (mass 4.98 kg) is moving to the right at 2.40 m/s. Block B (mass 2.49 kg) is moving to the left at 1.44 m/s. Block C (mass 3.80 kg) is at rest. What is the combined momentum of all 3 blocks?

Three blocks are sliding along a frictionless track. Block A (mass 4.98 kg) is moving to the right at 2.40 m/s. Block B (mass 2.49 kg) is moving to the left at 4.80 m/s. Block C (mass 3.80 kg) is at rest. What is the combined momentum of all 3 blocks?

Explanation / Answer

Here ,

let us assume right direction as positive

Now,

Momentum = mA*vA + mB*vB + mC*vC

Momentum = 4.98*2.4 + 2.49*1.44 + 3.80*0

Momentum = 15.54 Kg.m/s

the combined momentum of three blocks is 15.54 Kg.m/s

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