In the figure (Figure 1) , C 1 = C 5 = 8.4 ? F and C 2= C 3 = C 4 = 4.1 ? F . Th
ID: 1324432 • Letter: I
Question
In the figure (Figure 1) , C1 = C5 = 8.4?F and C2= C3 = C4 = 4.1?F . The applied potential is Vab = 230V .
What is the equivalent capacitance of the network between points a and b?
Calculate the charge on each capacitor and the potential difference across each capacitor.
In the figure (Figure 1) , C1 = C5 = 8.4?F and C2= C3 = C4 = 4.1?F . The applied potential is Vab = 230V . What is the equivalent capacitance of the network between points a and b? Calculate the charge on each capacitor and the potential difference across each capacitor.Explanation / Answer
C3 AND C4 ARE IN SERIES SO
Ceq=C3 + C4
Ceq=4.1 + 4.1
Ceq=8.2 F
NOW C1 ,C2,C5 ARE IN PARALLEL
SO
Ceq (1)=1/C1 +1/C2 +1/C5
Ceq(1)=1/8.4 + 1/4.1 + 1/8.4
Ceq(1)=2.074 F
Ceq and Ceq (1) are in series so'
Ceq(final)=2.074 + 8.2 F
Ceq(final )=10.274 F
TOTAL Charge=c * v
Q=C * V
Q=10.274 *230
Q=2363.02
For series strings the charge is the same, so this charge is on C3 & C4 with a voltage of V = Q/C = 2363.02 /4.1= 576.346 volts.
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