1) A point charge of +2 uC is 12 cm distant from a second point charge of -4 uC.

Question

1) A point charge of +2 uC is 12 cm distant from a second point charge of -4 uC. Calculate the magnitude of the force on each charge.

2) Find the equivalent capacitance of the circuit between points a and b. All capacitances in the circuit are given on the picture.

1) A point charge of +2 uC is 12 cm distant from a second point charge of -4 uC. Calculate the magnitude of the force on each charge. 2) Find the equivalent capacitance of the circuit between points a and b. All capacitances in the circuit are given on the picture.

Explanation / Answer

force between two point charges is given by F = Kq1q2/r^2

where q1 and a2 are the charges

and ris the distance between them

so

F = 9e9 * 2e-6 * 4e-6/(0.12*0.12)

F = -5 N ( attracti force this is )

----------------------------

Cnet in series = Cs = C1C2/(C1+C2)

Cnet in parallel = Cp = C1+ C2

so

here

Cp of 1pF and 3pF is Cp = 1+3 = 4 pF

this is in sereis with 2 and 2.5

so

1/Cnet = (1/2) +(1/2.5) +(1/4)

1/Cnet = 1.15

Cnet = 0.869 pF

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.