of kinetic friction between the ramp and the crate, Muk is equal to 0.200. How m
ID: 1324884 • Letter: O
Question
of kinetic friction between the ramp and the crate, Muk is equal to 0.200. How much work must you do to push the crate a distance of 2.00 m? 79. A 12.0-kg block (M) is released from rest on a frictionless incline that makes an angle of 28.0 degree, as shown in Figure 6-42. Below the block is a spring that has a spring constant of 13500 N/m. The block momentarily stops when it compresses the spring by 5.50 cm. How far does the block move down the incline from its rest position to the stopping point? SSM 80. Sports A man on his luge (total mass of 88.0 kg) emerges onto the horizontal straight track at the bottom of the hill with a speed of 28.0 m/s. If the luge and rider slow at a constant rateExplanation / Answer
The change in energy by the compressed spring is .5kx2 + mgh
The distance h = 5.5sin(28) = 2.58 cm
Energy = .5(13500)(.055)2 + (12)(9.8)(.0258) = 23.46 Joules
That must be the initial PE due to conservation of energy
PE = mgh
23.46 = (12)(9.8)(h)
h = .199 m
Then the total distance traveled is d = .199/(sin 28)
d = .425 m (42.5 cm)
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