In a downtown office building you notice each of the four sections of a rotating

Question

In a downtown office building you notice each of the four sections of a rotating door has a mass of 75 kg. What is the width of each section of the door if a force of 56 N applied to the outer edge of a section produces an angular acceleration of 0.410 rad/s2?
m

In a downtown office building you notice each of the four sections of a rotating door has a mass of 75 kg. What is the width of each section of the door if a force of 56 N applied to the outer edge of a section produces an angular acceleration of 0.410 rad/s2? m

Explanation / Answer

Here ,

let the width of each section be w

then

using second law of motion

4*1/3 *75 * w^2 *0.410 = 56 * w

solving for w

w = 1.37 m

the width of each section is 1.37 m

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