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PSS 8.1: Static equilibrium problems Learning Goal: To practice Problem-Solving

ID: 1325487 • Letter: P

Question

PSS 8.1: Static equilibrium problems

Learning Goal:

To practice Problem-Solving Strategy 8.1 Static equilibrium problems.

When you lift an object by moving only your forearm, the main lifting muscle in your arm is the biceps. Suppose the mass of a forearm is 1.50kg . If the biceps is connected to the forearm a distance dbiceps = 3.50cmfrom the elbow, how much force Fbiceps must the biceps exert to hold a 750g ball at the end of the forearm at distance dball = 37.0cm from the elbow, with the forearm parallel to the floor? How much force Felbowmust the elbow exert? (Figure 1)

What is the horizontal distance d forearm between the elbow and the point where the weight of the forearm acts?

Explanation / Answer

Given that,

mass of the forearm = m = 1.5 kg

dbicep =l = 3.50 cm = 0.035m

Mass of the ball = M = 750 g = 0.75 kg

dball =L= 37 cm = 0.37 m

Lets write an eqn for all the acting forces,

l.F(bicep) -1/2Lmg - LMg = 0

Solving the above eqn for F(bicep), we get

F(bicep) = { (1/2m + M ) Lg } / l = { (1/2x1.5kg + 0.75kg) 0.37 m x 9.8 m/sec2 } / 0.035 m

F(bicep) = 155.4 N

For calculating F(elbow)

L.F(elbow) - l F(bicep) -1/2 Lmg - LMg = 0, we get

F(elbow) = { lF(bicep) + Lg (1/2m + M) } / L = { (0.035 x 155.4 )+ 0.37 x 9.8 (1/2x1.5 + 0.75 ) } / 0.37

F(elbow) = 29.4 N

d(forearm) = 1/2L = 0.185 m

Dr Jack
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