A force in the + x -direction with magnitude F ( x ) = 18.0 N ? ( 0.530 N / m )

ID: 1325540 • Letter: A

Question

A force in the +x-direction with magnitudeF(x)=18.0N?(0.530N/m)x is applied to a 8.30kg box that is sitting on the horizontal, frictionless surface of a frozen lake. F(x) is the only horizontal force on the box. Part A If the box is initially at rest at x=0, what is its speed after it has traveled 16.0 A force in the +x-direction with magnitudeF(x)=18.0N?(0.530N/m)x is applied to a 8.30kg box that is sitting on the horizontal, frictionless surface of a frozen lake. F(x) is the only horizontal force on the box. Part A If the box is initially at rest at x=0, what is its speed after it has traveled 16.0 A force in the +x-direction with magnitudeF(x)=18.0N?(0.530N/m)x is applied to a 8.30kg box that is sitting on the horizontal, frictionless surface of a frozen lake. F(x) is the only horizontal force on the box. A force in the +x-direction with magnitudeF(x)=18.0N?(0.530N/m)x is applied to a 8.30kg box that is sitting on the horizontal, frictionless surface of a frozen lake. F(x) is the only horizontal force on the box. A force in the +x-direction with magnitudeF(x)=18.0N?(0.530N/m)x is applied to a 8.30kg box that is sitting on the horizontal, frictionless surface of a frozen lake. F(x) is the only horizontal force on the box. Part A If the box is initially at rest at x=0, what is its speed after it has traveled 16.0 Part A If the box is initially at rest at x=0, what is its speed after it has traveled 16.0 Part A If the box is initially at rest at x=0, what is its speed after it has traveled 16.0

Explanation / Answer

Here is what I solved before, please modify the figures as per your question. Please let me know if you have further questions. Ifthis helps then kindly rate 5-stars.

A force in the +x-direction with magnitudeF(x)=18.0N?(0.530N/m)x is applied to a 6.60kgbox that is sitting on the horizontal, frictionless surface of a frozen lake. F(x) is the only horizontal force on the box.

If the box is initially at rest at x=0, what is its speed after it has traveled 17.0m ?

Answer

work done = integral F(x). dx
= 18*x - 0.53*x^2/2

from x = 0 to x = 17 m

Work done = 18*17 - 0.53*17^2/2

= 229.415 J

work done = change in kinetic energy

0.5*m*v^2 = 229.415 j

v = sqrt(2*229.415/6.6) = 8.34 m/s

Navigate

A force has a magnitude of 10 N, and it is forming and angle of 30o with an x-ax

A force in the + x-direction with magnitude F(x) = 18.0 N – (0.530 n/m) x is app

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.

A force in the + x -direction with magnitude F ( x ) = 18.0 N ? ( 0.530 N / m )

Question

Explanation / Answer

Related Questions

Navigate