The figure shows a spherical conducting shell, inner radius a, and outer radius

Question

The figure shows a spherical conducting shell, inner radius a, and outer radius b, with a point charge + Q inside. In case (1) the point charge is at the center of the shell, and in case (2) it is off-center. Use Gauss’s law to predict the charge on the inner surface and on the outer surface of the shell, in each case. In each case, describe the electric field in the three regions r < a, a < r < b, and r > b. In the figures draw a typical electric field line starting from the charge, extending vertically in the diagram, and ending where you think it should end. If you feel the need, for clarity, draw a bigger diagram. I NEED A DIAGRAM WITH ANSWER OF ELECTRIC FIELD LINES. THAT IS WHY IM GIVING EXTRA POINTS FOR THIS ANSWER

The figure shows a spherical conducting shell, inner radius a, and outer radius b, with a point charge + Q inside. In case (1) the point charge is at the center of the shell, and in case (2) it is off-center. Use Gauss A s law to predict the charge on the inner surface and on the outer surface of the shell, in each case. In each case, describe the electric field in the three regions r

Explanation / Answer

In both the cases a charge of -Q will be induced on the inner surface and +Q will induced on the outer surface of sphere. because excess electrons mutually repel one another, and, thereby, become uniformly distributed over the surface of the shell. The electric field-lines produced outside such a charge distribution point towards the surface of the conductor, and end on the excess electrons. Moreover, the field-lines are normal to the surface of the conductor.

But in the second case the charge is off centre, so Charge distribution will not be uniform but the flux will be same.

We choose our Gaussian surface to be a sphere of radius r ? a
The charge enclosed by the Gaussian surface is qenc = 0 since all the charge is located on the surface of the shell. Thus, from Gauss

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