A straight, nonconducting plastic wire 7.50 cm long carries a charge density of

Question

A straight, nonconducting plastic wire 7.50 cm long carries a charge density of 100 nC/m distributed uniformly along its length. It is lying on a horizontal tabletop.

Part A

Find the magnitude and direction of the electric field this wire produces at a point 5.50 cm directly above its midpoint.

Part C

If the wire is now bent into a circle lying flat on the table, find the magnitude and direction of the electric field it produces at a point 5.50 cm directly above its center.

Exercise 21.54 Part A Find the magnitude and direction of the electric field this wire produces at a point 5.50 cm directly above its midpoint. A straight, nonconducting plastic wire 7.50 cm long carries a charge density of 100 nC/m distributed uniformly along its length. It is lying on a horizontal tabletop E- 5.80 104 N/C Submit My Answers Give Up Submit Incorrect; Try Again; 7 attempts remaining; no points deducted Part B electric field is directed upward electric field is directed downward Submit My Answers Give Up Correct Part C If the wire is now bent into a circle lying flat on the table, find the magnitude and direction of the electric field it produces at a point 5.50 cm directly above its center N/C Submit My Answers Give Up

Explanation / Answer

here ,

electric field due to rod ,

E = k * lamda * L/(R * sqrt((L/2)^2 + R^2))

E = 9*10^9 * 100 *10^-9 * 0.0750/(0.055 * sqrt((0.075/2)^2 + 0.055^2)

solving

E = 1.844 *10^4 N/C

the electric field due to rod is 1.844 *10^4 N/C

part C)

Now, for bending the wire in a circle

radius of circle , r = 7.5/2pi = 1.19 cm

E = k * lamda * x * L/(x^2 + R^2)^1.5

E = 9*10^9 * 100 *10^-9 * 0.055 * 0.075/(0.0119^2 + 0.055^2)^1.5

solving for E

E = 2.08 *10^4 N/C

the electric field due to ring is 2.08 *10^4 N/C

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