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PHY 112 Fall 2015 Help | Close Item 14 Resources previous | 14 of 16 | next » Item 14 What is the ratio of the electric force on the bee to the bee's weight? Express your answer using two significant figures A 0.15 g honeybee acquires a charge of 24 pC while flying The electric field near the surface of the earth is typically 100 N/C, directed downward Fe/W = Submit My Answers Give Up Incorrect; Try Again; 4 attempts remaining Part B What electric field strength would allow the bee to hang suspended in the air? Express your answer using two significant figures. 0? N/C Submit My Answers Give Up 11:26 PM 9/14/2015

Explanation / Answer

A)

Eectric force on the bee, Fe = q*E

= 24*10^-12*100

= 2.4*10^-9 N

wight of the bee, W = m*g

= 0.15*10^-3*9.8

= 1.47*10^-3 N

so, Fe/W = 2.4*10^-9/(1.47*10^-3)

= 1.63*10^-6 <<<<<<------------Answer

B)

when, Fe = W, be will be uquilibrium

q*E = m*g

==>E = m*g/q

= 0.15*10^-3*9.8/(24*10^-12)

= 6.125*10^7 N/c <<<<<<------------Answer

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