Two horses pull horizontally on ropes attached to a stump. The two forces F 1 =
ID: 1326369 • Letter: T
Question
Two horses pull horizontally on ropes attached to a stump. The two forces F1 = 1250 N and F 2 that they apply to the stump are such that the net (resultant) force R has a magnitude equal to that of F 1 and makes an angle of 90 with F 1. Find the magnitude of F 2.Find the direction of F 2 (relative to F1).
You have just landed on Planet X. You take out a ball of mass 100 g , release it from rest from a height of 13.0 m and measure that it takes a time of 2.50 s to reach the ground. You can ignore any force on the ball from the atmosphere of the planet.How much does the ball weigh on the surface of Planet X?
A loaded elevator with very worn cables has a total mass of 2600 kg , and the cables can withstand a maximum tension of 3.00×104 N .
Apply Newton's second law to the elevator and find the maximum upward acceleration for the elevator if the cables are not to break?
What would be the answer to part B if the elevator were on the moon, where free fall acceleration is g = 1.62 m/s2
A student tries to raise a chain consisting of three identical links. Each link has a mass of 300 g . The three-piece chain is connected to a string and then suspended vertically, with the student holding the upper end of the string and pulling upward. Because of the student's pull, an upward force of 12 N is applied to the chain by the string. Use Newton's laws to answer the following questions.
Find the acceleration of the chain.
Find the force exerted by the top link on the middle link.
Explanation / Answer
A loaded elevator with very worn cables has a total mass of 2600 kg , and the cables can withstand a maximum tension of 3.00×104 N .
Apply Newton's second law to the elevator and find the maximum upward acceleration for the elevator if the cables are not to break?
What would be the answer to part B if the elevator were on the moon, where free fall acceleration is g = 1.62 m/s2
Answer :
Applying Newton's second law to the elevator,
T-mg=ma
T=mg+ma
=m(g+a)
3.00×104 N=2600 kg(9.8 m/s^2+a)
a=1.738 m/s^2
If the system is on the moon
3.00×104 N=2600 kg(1.62 m/s^2+a_moon)
a=9.92 m/s^2
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