A cube with 1.40 m edges is oriented as shown in the figure in a region of unifo

Question

A cube with 1.40 m edges is oriented as shown in the figure in a region of uniform electric field. Find the electric flux through the right face if the electric field, in newtons per coulomb ( N/C), is given by 8.20i. (N*m(shift-6)2/C)

Find the electric flux through the right face if the electric field, in newtons per coulomb ( N/C), is given by -3.60j.

Find the electric flux through the right face if the electric field, in newtons per coulomb ( N/C), is given by -2.80i + 3.00k.

What is the total flux through the cube for each of these fields?

Explanation / Answer

Here ,

for the right face

Flux = E . A

flux = 8.20 i . (1.4^2 j)

flux = 0

the electric flux through the right face is 0 N.m^2/C

for E = -3.60 j

Flux = E . A

flux = -3.6 i . (1.4^2 j)

flux = - 7.06 N.m^2/C

the electric flux through the right face is - 7.06 N.m^2/C

for E - -2.80 i + 3 k

Flux = E . A

flux = ( -2.80 i + 3 k ) . (1.4^2 j)

flux = 0 N.m^2/C

the electric flux through the right face is 0 N.m^2/C

as the eletric field is uniform ,

according to gauss law ,

the net electric flux due to these fields is ZERO

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