A flat sheet of paper of area 0.130 m2 is oriented so that the normal to the she

Question

A flat sheet of paper of area 0.130 m2 is oriented so that the normal to the sheet is at an angle of 56 to a uniform electric field of magnitude 18 N/C .
Part A:

Find the magnitude of the electric flux through the sheet.
Part c:

For what angle between the normal to the sheet and the electric field is the magnitude of the flux through the sheet largest?
Part B:
Does the answer to part A depend on the shape of the sheet?
Part D;
For what angle between the normal to the sheet and the electric field is the magnitude of the flux through the sheet smallest?
Part E:
Explain your answers in parts C and D.

Explanation / Answer

here,

area of flat sheet , A = 0.13 m^2

magnitude of electric feild , E = 18 N/C

theta = 56 degree

part A)

the magnitude of the electric flux through the sheet , flux = E * A * cos(theta)

flux = 18 * 0.13 * cos(56)

flux = 1.31 N.m^2/C

the magnitude of the electric flux through the sheet is 1.31 N.m^2/C

part B )

the angle between the normal to the sheet and the electric field is 0 degree for the magnitude of the flux through the sheet largest

part C )

No , the answer of part A does not depend on the shape of sheet

part D)

the angle between the normal to the sheet and the electric field is 90 degree for the magnitude of the flux through the sheet smallest

part E )

as flux = E * A * cos(theta)

for largest value , cos(theta) = 1

then theta = 0 degree

for the smallest value

cos (theta) = 0

then , theta = 90 degree

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