Not sure what I am doing wrong here,assignment is due tomorrowmorning, help? =/

Question

Not sure what I am doing wrong here,assignment is due tomorrowmorning, help? =/
1.)A proton follows the path shown in (Figure 1)
https://d2vlcm61l7u1fs.cloudfront.net/media%2F79b%2F79b4ead0-dc71-4eef-ad75-24715d0279dd%2FphpLgy9DN.png
Its initial speed is v0 = 2.2×106 m/s .

What is the proton's speed as it passes through point P? Express your answer to two significant figures and include the appropriate units

MasteringPhysics: CH 21 HW https://session.masteringphysics.com/myctitemView?assignmentProblemID-54421116 a search PHY 112 Fall 2015 Help Close CH21 HWItem 5 Resources « previous | 5 of 10 | next»- Item 5 c Because the proton is a positive charge and it slows down as it travels, it must be moving from a region of higher potential to a region of lower potential gion of hiaher potential to MasteringPhysics: CH 21 HW https://session.masteringphysics.com/myctitemView?assignmentProblemID-54421116 a search PHY 112 Fall 2015 Help Close CH21 HWItem 5 Resources « previous | 5 of 10 | next»- c Because the proton is a negative charge and it accelerates as it travels, it must be moving from a region of higher potential to a Item 5 region of lower potential Submit My Answers Give Up A proton with an initial speed of 900,000 m/s is brought to rest by an electric field Correct Part B What was the potential difference that stopped the proton? Express your answer to two significant figures and include the appropriate units Submit My Answers Give Up swer Incorrect Iry Again, 4 attempts remaining Part C What was the initial kinetic energy of the proton, in electron volts? Express your answer using two significant figures

Explanation / Answer

given,

initial velocity of the proton = 2.2 * 10^6 m/s

force between two charged particles = kq1 * q2 / d^2

force = 9 * 10^9 * -10 * 10^-9 * 1.6 * 10^-19 / (3 * 10^-3)^2

force = 1.6 * 10^-12 N

force = mass * acceleration

1.6 * 10^-12 = 1.67 * 10^-27 * acceleration

acceleration = 9.58 * 10^14 m/s^2

v^2 = u^2 + 2as

v^2 = 2 * 9.58 * 10^14 * 3 * 10^-3

v = 2397498.69656 m/s

resultant velocity = sqrt(2397498.69656^2 + ( 2.2 * 10^6)^2)

velocity at point p = 3253920.712 m/s

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