You are attending a rock concert and you are 40.0 m from the stage, and at this

Question

You are attending a rock concert and you are 40.0 m from the stage, and at this point the sound intensity level is 114 dB . Sound is detected when a sound wave causes the tympanic membrane (the eardrum) to vibrate . Typically, the diameter of this membrane is about 8.40 mm in humans

Part A

How much energy is transferred to your eardrums each second ?

Part B

How fast would a 2.00 mg fruit fly have to fly to have this much kinetic energy?

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Part C

How fast a typical 2.0 mg fruit fly would have to fly (in mm/s) to have an amount of energy delivered to the eardrum each second when someone whispers (20 dB) a secret in your ear?

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Part D

Compare the fruit fly's speeds found in parts (B) and (C).

Please enter your answer as a number (factor) without the units.

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You are attending a rock concert and you are 40.0 m from the stage, and at this point the sound intensity level is 114 dB . Sound is detected when a sound wave causes the tympanic membrane (the eardrum) to vibrate . Typically, the diameter of this membrane is about 8.40 mm in humans

Part A

How much energy is transferred to your eardrums each second ?

E = J

Part B

How fast would a 2.00 mg fruit fly have to fly to have this much kinetic energy?

v = m/s

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Part C

How fast a typical 2.0 mg fruit fly would have to fly (in mm/s) to have an amount of energy delivered to the eardrum each second when someone whispers (20 dB) a secret in your ear?

v = mm/s

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Part D

Compare the fruit fly's speeds found in parts (B) and (C).

Please enter your answer as a number (factor) without the units.

v = v

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Explanation / Answer

Part A

I = (10^-12 W/M^2)*10^(114/10)
I = 0.251188 W/M^2

Then, knowing the intensity per unit area I multiplied the I by the surface area of the eardrum, which is

pi*(0.00420 m)^2* 0.251188 W/m2

E = 13.9 J

Part B

Ke = 0.5*m*v2

Thus I have: v = sqrt(2*(0.0000139203 kgm^2/s^2)/2 *10^-6 kg) v = 3.730 m/s

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