A fireman d= 33m away from a burning building directs a stream of water from a g

Question

A fireman d= 33m away from a burning building directs a stream of water from a ground level fire hose at an angle of 36 degrees above the horizontal as shown in the figure. If the speed of the stream as it leaves the hose is vi= 40 m/s, at what height will the stream of water strike the building? A fireman d= 33m away from a burning building directs a stream of water from a ground level fire hose at an angle of 36 degrees above the horizontal as shown in the figure. If the speed of the stream as it leaves the hose is vi= 40 m/s, at what height will the stream of water strike the building?

Explanation / Answer

Here ,

theta =36 degree

vi = 40 m/s

d = 33 ,

let the height is h
using equation of trajectory of projectile

h = x * tan(theta) - g * x^2/(2 *(v * cos(theta))^2)

h = 33 * tan(36) - 9.8 * 33^2/(2 * (40 * cos(36))^2)

h = 18.9 m

the height where water strike is 18.9 m

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