Eleven point charges of magnitude-q are arranged in a circle as shown in The fig

Question

Eleven point charges of magnitude-q are arranged in a circle as shown in The figure below. object of mass 0.012 kg (big enough to consider gravity!) is in a constant downward electric field of 3.31timesl04 N/C. It has a total downward acceleration of 2 20 m/s when it is released from rest. Draw a free body diagram of The charge. Sum The forces on The charge. How much charge is on The object? Give magnitude and also whether it is positive or negative. How fast is The charge going after it has fallen 2.00 m? How much have The following forms of energy changed (final minus initial) in that 2.00m fall? (Be sure to watch your signs.) Electric potential energy Gravitational potential energy Kinetic energy Total energy environment which condones The use of unauthonzed aid.

Explanation / Answer

5,

a)

Total Electric potential at center is given as

V = - k q/r2 - k q/r2 - k q/r2 - k q/r2 - k q/r2 - k q/r2 - k q/r2 - k q/r2 - k q/r2 - k q/r2 - k q/r2

V = - 11k q/r2

b)

By symmetry , charges at opposite ends cancel out there electric fields.

for 11 charges , we have 5 pairs . so 10 charges cancel out their electric field . remaining 1 charge produce electric field which is given as

E = kq/r2

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