1) If you are standing on a building 46 m tall and you want to throw a water bal

Question

1) If you are standing on a building 46 m tall and you want to throw a water balloon on a person's head who is 1.80 m tall and walking towards the building at a constant speed of 1.20m/s. Where should the person be when you release the ball?

2) An object is thrown vertically upwards. It passes point A with a speed v, and point B which is 3.00m above A with speed 1/2 v. Find v and the maximum height reached above point B.

3) A ball is thrown vertically upwards, it takes 5 seconds to hit the ground. what is the initial speed of the ball?

Explanation / Answer

1) S=ut+1/2 at2

46-1.8 =0+1/2 x9.8 t2

t2=44.2/4.9

t =3 s

S =ut+0

S = 1.2x3=3.6 m

2) v2- u2 =2as

For point A ... v2- u2 = 2as

v2- u2 = -2gh ..(1)

For point B

(v/2)2- u2 = -2g(h+3).. (2)

(1)-(2)

3v2/4 = 2g3

v =8.85 m/s

3) u= gt/2=9.8x5/2 =24.5 m/s

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