Projectile Motion Tutorial Part A Learning Goal Find the time tH it takes the pr

Question

Projectile Motion Tutorial Part A Learning Goal Find the time tH it takes the projectile to reach its maximum height H Express tH in terms of vo, , and g (the magnitude of the acceleration due to gravity) To understand how to apply the equations for one- dimensional motion to the x and y directions separately in order to derive standard formulas for the range and height of a projectile ground level at time (Figure 1) A projectile is fired from t 0, at an angle with respect to the horizontal. It has an initial speed vo. In this problem we are assuming that the ground is level Hints My Answers Give Up Review Part Figure 1 of 1 Part B Find tR, the time at which the projectile hits the ground after having traveled through a horizontal distance R Express the time in terms of vo, 0, and g Submit Hints My Answers Give Up Review Part Part C Find H, the maximum height attained by the projectile Express your answer in terms of U0,9, and g

Explanation / Answer

Here ,

part A)

let the time taken to maximum height is tH

as the final speed is 0 at the maximum height

tH = v0 * sin(theta)/g

the time taken to reach maximum height is v0 * sin(theta)/g

B)

Here , as time taken to come down frommaximu height is sane as

the time taken to reach Hmax

tR = 2 * tH

tR = 2*v0 * sin(theta)/g

C)

using third equation of motion

v^2 - u^2 =2 * a * h

0 - (v0* sin(theta))^2 = -2 * g * H

H = vy^2/(2 *g)

maximum height = (v0*sin(theta))^2/(2 *g)

d)

the range of projectile is given as

Range , R = v0^2 * sin(2 * theta)/g

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.