KINEMATICS IN ONE DIMENSION Water drips from a shower head (the sprayer at the t
ID: 1329058 • Letter: K
Question
KINEMATICS IN ONE DIMENSION
Water drips from a shower head (the sprayer at the top of the shower) and falls onto the floor 2.5 m below. The droplets are falling at regular intervals (equal amounts of time between drops), with the first drop hitting the floor at the instant that the fourth drop starts to fall.
When the first drop hits the floor (as the fourth drop is dripping from the shower head), how far below the shower head is the third drop? [The third drop is the one that fell right before the fourth drop.]
Explanation / Answer
let t be the time interval between each drop
the time taken by the first drop to reach the floor = 3t
for the first drop
from the equationog motion
dy = vo*t + 0.5*g*T^2
dy = -2.3
g = -10 m/s^2
T = 4t
vo = 0
-2.5 = -0.5*10*(3t)^2
t = 0.24 s
by the time first drop hits the floor the 3rd drop travelled for time t = 0.24 s
distance travelled by 3 rd drop
-y = -0.5*10*0.24^2
y = 0.28 m <<--------------answer
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.